Y=4.9x^2+30x+12

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Solution for Y=4.9x^2+30x+12 equation:



=4.9Y^2+30Y+12
We move all terms to the left:
-(4.9Y^2+30Y+12)=0
We get rid of parentheses
-4.9Y^2-30Y-12=0
a = -4.9; b = -30; c = -12;
Δ = b2-4ac
Δ = -302-4·(-4.9)·(-12)
Δ = 664.8
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-30)-\sqrt{664.8}}{2*-4.9}=\frac{30-\sqrt{664.8}}{-9.8} $
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-30)+\sqrt{664.8}}{2*-4.9}=\frac{30+\sqrt{664.8}}{-9.8} $

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